(-2x^-4/4y^-3)^-1

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Solution for (-2x^-4/4y^-3)^-1 equation: 


D( x )

((-2*x^-4)/4)*y^-3 = 0

x = 0

((-2*x^-4)/4)*y^-3 = 0

((-2*x^-4)/4)*y^-3 = 0

-1/2*x^-4*y^-3 = 0 // : -1/2*y^-3

x^-4 = 0

x naleu017Cy do O

x = 0

x = 0

x in (-oo:0) U (0:+oo)

(((-2*x^-4)/4)*y^-3)^-1 = 0

-2*x^4*y^3 = 0 // : -2*y^3

x^4 = 0

x = 0

x in { 0} 

x belongs to the empty set

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